Why the "P3D renderer is not in the class path"?

py5
1

i’m begging to use Py5Graphics with the command:

pg = py5.create_graphics( 500, 500, ‘P3D’)

and later when i begin to draw into this window, i get the error:

“The P3D renderer is not in the class path”

How is the class path specified?

thank you.

2

This runs without error in Thonny:

import py5

def setup():
    global pg
    
    py5.size(400, 400, py5.P2D)
    pg = py5.create_graphics(40, 40, py5.P3D)

py5.run_sketch()

Documentation is here if you haven’t already seen it:

2 Likes
3

We’re supposed to use the already-defined constant P3D for the renderer parameter:

Which corresponds to the string 'processing.opengl.PGraphics3D'; not 'P3D':

pg = py5.create_graphics(500, 500, py5.P3D)

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4

ok, but when i use:

pg = py5.create_graphics(600,600, py5.P3D)

then when it gets to the code:

pg.rotate_x(rx)

i get the error:

rotateX() can only be used with a renderer that supports 3D, such as P3D

can you tell what i’m doing wrong from this?

1 Like
5

In order to create_graphics() w/ constant P3D, it’s also required to call size() w/ P3D or P2D:

1 Like
6

Hello @larrycuba ,

A working example using a rotation in the PGraphic and outside of it:

import py5

global pg
global counter
global angle

def setup():
    py5.size(200, 200, py5.P3D)

    global counter
    global angle
    counter = 0
    angle = 0

    global pg
    pg = py5.create_graphics(60, 60, py5.P3D)
    
    pg.begin_draw()
    pg.background(100, 0)
    pg.lights()
    pg.no_stroke()
    pg.fill(255, 0, 0)
    pg.translate(30, 30)
    pg.rotate(py5.TAU / 8, 0, 1, 0)
    pg.box(25)
    pg.end_draw()

def draw():
    global counter
    global angle
    
    py5.background(200)

    py5.translate(py5.width / 2, py5.height / 2)
    py5.image_mode(py5.CENTER)
    counter += 1
    angle = counter * (py5.TAU / 360)
    py5.rotate(angle, 0, 1, 0)
    py5.image(pg, 0, 0)

py5.run_sketch()

This is the environment I am using:

:)

1 Like