Using open() in processing 2

Processing Coding Questions
1

I know launch is the new open in 3.0+
but I use open to run .exe 's and everything works fine.

I want to rename a file using open and the cmd .exe
i tried:

open(“rename c:\path\file.fil file.bak”)

and nothing happens , no error but .bak fil is not created
same line at command prompt works fine , so syntax is correct.

Also tryed putting cmd.exe before rename , same result.

Should be able to invoke command sthe same as command line right?
Am I missing something in the syntax for open to work?

Thanks

1 Like
2

I thought that launch and exec were both present in both 2.0 and 3.0 – and only launch was listed on the reference, but both are in the API.

I’m not as familiar with the Windows command line – I can only test on Linux / Mac, so I can’t answer your question.

You might want to try exec, which is mentioned in the launch reference and described in the API linked from the top of each reference page.

3

Thanks for your reply.
I tryed exec and launch and both give not recognized error
i’m using 2.2.1

Will do it again in smaller context test sketch to make sure.
thanks
Jeff

4

Apologies if I was wrong about exec() – I don’t have Processing 2.2.1 on this machine for a quick check. Could download and check the reference folder for the API files.

If the object to be renamed is static, a workaround might be to open a script (e.g. a bat file) referenced by static name, and put your rename command and argument in that file. Use open on the bat. Untested as I am not on Windows.

5

Docs.Oracle.com/en/java/javase/11/docs/api/java.base/java/io/File.html#renameTo(java.io.File)