With G4P Click Checkbox also triggers mouseClicked

Processing Libraries
1

With a G4P Checkbox when I click on it, the Processing mouseClicked() runs as well. In other environments where I’ve coded, the front-most window gets the click and doesn’t arrive on the ones behind. I’m finding myself adding code to the mouseClicked() to ignore the click if it’s on the Checkbox.

Am I missing the reason why it’s like this? Is it selectable not to have the mouseClick as well?

import g4p_controls.*;
GCheckbox cBox;
public void setup(){cBox = new GCheckbox(this, 20, 10, 80, 20, "CBox");}
void draw() {}
void mouseClicked() {println("mouseClicked");}
2

G4P registers itself with Processing so gets a copy of Processing events. It does not replace Processing’s event handling system.

So when you click the mouse button Processing triggers a mouse clicked event which causes the mouseClicked function to be executed. G4P also gets a copy of the event which it will process if the mouse is over a G4P control.

It is just how Processing works with third party libraries.

True but there is only one “window” in the sketch code you posted.

3

Thank you. Always good to know more of how it all works. I was thinking that the mouseClicked() code would have to know the coords of all the CheckBoxes. Now I’ve found that the G4P code runs before mouseClicked(). So it can set a boolean to indicate that the mouseClick should be ignored. Much more tidy.

import g4p_controls.*;
GCheckbox cBox;
boolean G4PClicked = false;
public void setup(){cBox = new GCheckbox(this, 20, 10, 80, 20, "CBox");}
void draw() {}
public void handleToggleControlEvents(GToggleControl checkbox, GEvent event) {G4PClicked = true;}
void mouseClicked() {
  if (G4PClicked) {G4PClicked = false;}
  else {print("mouseClicked ");}
}
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