Switch case with two key pressed? Is it possible?

Processing Coding Questions
1

Hello.

I would like to switch case with a combination of two letter or letter, one of each.

I did like that, but it doesn’t work

void keyPressed() {
  
      if (key=='5' && key=='T'){ 


println ("T55555TTTT5555");
   
      }
      
      if (key=='7'){       
          
     
             println ("CASE 7 PRRRRRRRRRRRRRRRREEEEEEEEEEEESSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSEDDDDDDDDDD"); 

      }
          
  
   if (keyCode == LEFT && key=='1') {
  
        println ("LEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFTLEFT11111111111111");
       
}  

 else if (keyCode == DOWN && key=='2') {/
  
        println ("DOWNDOWNDOWNDOWNDOWNDOWNDOWNDOWNDOWNDOWNDOWNDOWNDOWNDOWNDOWNDOWNDOWNDOWNDOWNDOWN222222222222222222222");    
}  
}

Thanks

1 Like
2

You can’t use boolean operators with switch statements.

https://docs.oracle.com/javase/tutorial/java/nutsandbolts/switch.html

Use the if/else…

1 Like
3

I have tried to adapt an example but it doesn’t work

 int month = 1;
 String monthString;
 
public void settings() {
  
   size(600, 600);
 
  }
  
void setup() {
  }

void draw () {
  
  keyPressed ();
  
   }
void keyPressed () {
  
  
 if (  key=='1' &&  key=='2' ) { 
   
  // if (  key=='2') {
     month =12 ;
 //  } 
 }
  
switch (month) {
  
  
            case 1:  monthString = "January";
                     break;
            case 2:  monthString = "February";
                     break;
            case 3:  monthString = "March";
                     break;
            case 4:  monthString = "April";
                     break;
            case 5:  monthString = "May";
                     break;
            case 6:  monthString = "June";
                     break;
            case 7:  monthString = "July";
                     break;
            case 8:  monthString = "August";
                     break;
            case 9:  monthString = "September";
                     break;
            case 10: monthString = "October";
                     break;
            case 11: monthString = "November";
                     break;
            case 12: monthString = "December";
                     break;
            default: monthString = "Invalid month";
                     break;
        }
        System.out.println(monthString);
    
  }
4

keyPressed() creates an event listener, so no need to call it in draw().

Not sure what you are going to do when the user needs to input November, but any case here is one way to accomplish what you are trying to do …

boolean[] keys;
boolean wasMultiPress = false;
final int NUM_KEYS = 2;
color col = color(3, 7, 11);
String monthString = null;

void setup() {
  size(200, 200);
  background(col);
  keys = new boolean[NUM_KEYS];
  for (int i = 0; i < NUM_KEYS; i++) {
    keys[i] = false;
  }
}

void draw() {
  background(col);

  if (keys[0] && keys[1]) {
    wasMultiPress = true;
  }
}

void updateMonth(int m) {
  switch (m) {

  case 1:  
    monthString = "January";
    break;
  case 2:  
    monthString = "February";
    break;
  case 3:  
    monthString = "March";
    break;
  case 4:  
    monthString = "April";
    break;
  case 5:  
    monthString = "May";
    break;
  case 6:  
    monthString = "June";
    break;
  case 7:  
    monthString = "July";
    break;
  case 8:  
    monthString = "August";
    break;
  case 9:  
    monthString = "September";
    break;
  case 10: 
    monthString = "October";
    break;
  case 11: 
    monthString = "November";
    break;
  case 12: 
    monthString = "December";
    break;
  default: 
    monthString = "Invalid month";
    break;
  }
  println(monthString);
}

void keyPressed() {
  if (key == '1') {
    keys[0]=true;
  }

  if (key == '2') {
    keys[1]=true;
}
}
void keyReleased() {
  if (key == '1') {
    keys[0]=false;
  }

  if (key == '2') {
    keys[1]=false;
  }

  if (!keys[0] && !keys[1] && wasMultiPress) {
    updateMonth(12);
    wasMultiPress = false;
  } else {
    updateMonth(Character.getNumericValue(key));
  }
}
1 Like
5

:grinning:
Thank you Mister.

And How could I do a case with for example the keypad DOWN and the keypad 1.
Or the keypad A and the keypad 1 ?

6

You can up the number of array elements in keys, then add those checks in keyPressed()/keyReleased() …

then add to the if/else checking if multiple keys were selected or just single key.

At this point I would move that logic into it’s own function, ex. checkIfMultipleKeys() and invoke that in keyReleased().

keep in mind most keyboards only detect 2 keys being pressed at same time.

7

Studio.ProcessingTogether.com/sp/pad/export/ro.9cfU11egvzT6G

1 Like
8

Ok it works with two keys together

static final String TABULAR = "\t";
static final color FG = #FF0000, BG = 255;
static final int KEYS = 0500, SMOOTH = 3;
static final float FPS = 120.0, WEIGHT = 1.0;
 
final boolean[] keysDown = new boolean[KEYS];
 
void setup() {
  size(01000, 0500);
  smooth(SMOOTH);
  frameRate(FPS);
 
  colorMode(RGB);
  strokeWeight(WEIGHT);
  stroke(BG);
}
 
void draw() {
  final int p = frameCount % width;
  line(p, 0, p, height);
  for (int k = 0; k < KEYS; )  if (isKeyDown(k++))  set(p, k, FG);
  
    processTwoKey();
}
 
void keyPressed() {
  processKey(keyCode, true);
  println(keyCode + TABULAR);
}
 
void keyReleased() {
  processKey(keyCode, false);
}
 
void processKey(final int k, final boolean isDown) {
  if (k < KEYS)  keysDown[k] = isDown;
  

}

void  processTwoKey (){//final int k, final boolean isDown) {
  
   if (keysDown[65]== true &&  keysDown[40]== true) //  && keysDown[49] = true ) 

  println (" two keys together!!! ");
  
  }
 
boolean isKeyDown(final int k) {
  return keysDown[k];
}
1 Like