Repeat text x times

Processing Coding Questions
1

how do i print a letter, x times?

for example, an a repeated 6 times would be aaaaaa

1 Like
2

you can use a for loop

for(int i=0; i<6; i++) {
     print("a");
}
println("");

or

for(int i=0; i<6; i++) {
     text("a", 
         33+11*i, 44);
}
2 Likes
3 
Double x=Double.POSITIVE_INFINITY-1;

for(int i=0; i<x; i++) 
     print("a");

this is kind of awesome

2 Likes
4

If you want a usable String instead of printing directly to the console, you can use StringBuffer for performance:

String s;
char c = 'a';
long x = 100; // how many times to concatenate
StringBuffer buffer = new StringBuffer();
for(int i = 0; i < x; i++) {
  buffer.append(c);
}
s = buffer.toString();
println(s);
2 Likes
5

@MoonAlien822,

Can you explain what this is doing?

:)

1 Like
6

It (almost i need one more thing) runs a program that would output the lowest number possible, it’s not possible because it would repeat 0 forever, but when im done it should place a one at the end (which once again is not possible because the 0 would repeat forever) if we ever find the highest number possible you could switch Double.POSITIVE_INFINITY-1 with that number, and boom lowest number possible

7

this is the complete code:

Double x=Double.POSITIVE_INFINITY-1;
int i=0;
if (i==0){
  print(0.);}
for( i=0; i<x; i++) 
     print(0);
     
     if (i==x){
       print(1);}
8

this would be the output if we assumed googol as the highest number possible:

0.00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001

9

Only this is the for loop

The for loop ends after this line

To include more lines in the for loop use { }

Not sure what you try to achieve

10

Did you try println (Double.POSITIVE_INFINITY);

11

@Chrisir i explained what i tried to achieve here

12

and gave an example here

13

oh i see what i did wrong

here is the new version:

double x=Double.POSITIVE_INFINITY;
int i=0;

void draw(){
if (i==0){
  print(0.);}
  
for( i=0; i<x; i++) 
     print(0);
     
     if (i==x){
       print(1);}}
14

@Chrisir i hope this makes more sense

15

You need { after that

16

This can never be true

17

already said that here

18

because the for loop only runs up to i<x

19

if you change the x to a non infinite number it works just fine

20

by the way, I think print and println are a bit buggy. Eventually they stop working