Loop after loop in setup

Processing Coding Questions
1

If i want to use a specific loop for two different functions inside the draw what am i suppose to do??
For example if i want to use this :

for (int i=0; i<table.getRowCount(); i++) {

for two different function inside setup, must i write it like this?

void setup() {
   for (int i=0; i<table.getRowCount(); i++) {
   float y=table.getFloat(i, "y");
   table.sortReverse("y")
   float max_y= table.getFloat(0, "y")
   float y2=max_y/2;
  }
   for (int i=0; i<table.getRowCount(); i++) {
   float y=table.getFloat(i, "y")
            if (y>y2) {
      println("Everything is ok");
    }
  }
}
2

From what I understand in your question, it depends on what you need. For loops just keep repeating whatever is within it until a condition is met.

I pretty sure for your scenario you would need 2 for loops, because you would need to sort an whole array before checking it.

However you should be careful when using max_y in your second for loop because it is declared in the first one making it inaccessible in the second one. (Unless you have it declared as a global variable elsewhere)

3

Yeah that’s my problem…I want to use the variable max_y in the second loop to check the other values but i don’t know how to do it…
My problem is very simple: one for loop finds a max value for a table that i load and divide it by 2 and the other same for loop check if there are values above max_y/2.

4

You can have

float max_y= table.getFloat(0, "y");
float y2=max_y/2;

After the first for loop then, because the data will be sorted after it, and you can get the maximum value like you did before.

5

You mean this:

  for (int i=0; i<table.getRowCount(); i++) {
  }
  float y=table.getFloat(0, "ECG");
  table.sortReverse("ECG");
  float  max_y= table.getFloat(0, "ECG");

  println(max_y);
  for (int i=0; i<table.getRowCount(); i++) {
    float a=table.getFloat(i, "ECG");
    if (a>max_y) {
      println("Everything is ok");
    }
6

Yes, except you don’t need y anymore. If you want to check if anything is above half of max_y it should be a>max_y/2