what’s wrong with my code? It should be print out “4” for “sato”'s appearance times
String[]lines= loadStrings("data.txt");
String[]sato= loadStrings("keyword.txt");
int count=0;
for (int i=0; i<lines.length; i++) {
String[]tokens=split(lines[i], ",");
for (int j=0; j<tokens.length; j++) {
if (tokens[j].equals(sato)) {
count++;
}
}
}
println(count);
sato,tanaka,yoshida,kida
saito,kawada,tanaka,sato
mizuno,hirayama,sato,kida
utsunomiya,sato,kawada
sato
You are doing it wrong
z is always hence you check only the first line
Before the split statement you need an outer for loop to loop over the lines with z
Then the inner for loop iterates over the components of the current (z) line
It’s called a nested for loop, a loop inside a loop. Think of a grid.
Chrisir
Thank you ! Chrisr !
is the following code correct?
String[]lines= loadStrings("data.txt");
String[]sato= loadStrings("keyword.txt");
int count=0;
for (int i=0; i<lines.length; i++) {
String[]tokens=split(lines[i], ",");
for (int j=0; j<tokens.length; j++) {
if (tokens[j].equals(sato)) {
count++;
}
}
}
println(count);
Thank you matheynen!
I changed the program code,
I still want to use the equals to solve them…
is it right?
It looks okay to me
Does it work?
The equals should be okay
but it printed 0 , not 4 (T_T)
This gives an array
Hence you need to say sato [0] in the line with equals
this version below works
maybe you need to use the size() command at the start
use println() to check if the content is loaded correctly
String[]lines=
{
"sato,tanaka,yoshida,kida",
"saito,kawada,tanaka,sato",
"mizuno,hirayama,sato,kida",
"utsunomiya,sato,kawada",
};
String sato= "sato";
int count=0;
for (int i=0; i<lines.length; i++) {
String[]tokens=split(lines[i], ",");
for (int j=0; j<tokens.length; j++) {
if (tokens[j].equals(sato)) {
count++;
}
}
}
// ------------------------------------------------------
println(count);
Thank you 
Chrisir ! I solved the problem successfully!
Hint:
.equals(sato);
is not the same as:
.equals(“sato”);
https://processing.org/reference/String_equals_.html
In my sketch the name of the variable is the same as the content
When using loadStrings, it should be sato[0]
here is a way to use IntDict
IntDict inventory;
String[] lines, words;
String find = "Lorem";
boolean gotit = false;
long startT, stopT, dT;
void setup() {
size(200, 200);
inventory = new IntDict();
lines = loadStrings("http://websitetips.com/articles/copy/lorem/ipsum.txt");
for ( String l : lines ) {
words = split(l, ' ');
for ( String word : words ) inventory.add(word, 1);
}
println(inventory);
println("we have "+inventory.size()+" entries");
startT = millis();
inventory.sortKeys(); // sort alphabetically
gotit = inventory.hasKey(find); // look for search string
stopT = millis();
dT = stopT - startT;
if ( gotit ) {
println("Yes, we found _" + find + "_: " + inventory.get(find) + " times");
} else {
println("Sorry, no _" + find + "_");
}
println(" and needed for sort and search " + dT + " msec" );
}
Hi Henry,
I’m a little late to answer, but personally I enjoy using regex matching to solve problems like this.
You could try the following:
String text = join(loadStrings(“data.txt”), ",");
String sato = loadStrings(“keyword.txt”)[0];
String[] matches = match(text, "("+sato+")");
println(matches.length);
I haven’t tested this to see if it works for your case, but I think it should. I might try it later when I have access to processing.
Quick update:
matchAll is the function I should have been using. The following code works as desired:
String text = join(loadStrings("words.txt"), ",");
String sato = loadStrings("keyword.txt")[0];
String[][] matches = matchAll(text, "("+sato+")");
println(matches.length);
Thank you glv! ill try it!
Thank you graysonh! ill try it later!
Thank you kll! this is a good idea too!