I have to check if a file is exist in data folder while the code is running. How to achieve that function?

File f = dataFile("DoIExist.txt"); String filePath = f.getPath(); boolean exist = f.isFile(); println(filePath, exist);

It works in java mode. Thanks!! By the way, could you please tell me how to achieve that in python mode if possible?

Or is there any function to get current processing data folder’s path?

You can do that in python like this: import os def setup(): size(400,400) print(os.listdir('.')) print('someFile.txt' in os.listdir('.')) ‘.’ indicates your current path, and ‘..’ goes back one folder up. If you’re storing files in data folder, then you need to check inside 'data/' in…

[image] newton45: … how to achieve that in Python Mode if possible? f = this.dataFile('DoIExist.txt') filePath, exist = f.path, f.isFile() print filePath, exist

[image] newton45: Or is there any function to get current processing data folder’s path? Yes! Just pass an empty string "" to dataPath(): dataFolderPath = this.dataPath('') + '/' print dataFolderPath … or to dataFile(): dir = this.dataFile('') dataFolderPath = dir.path + '/' print dataFold…

How to check if a file is exist in data folder by code?

Processing.py

GoToLoop June 1, 2018, 5:17am 6

f = this.dataFile('DoIExist.txt')
filePath, exist = f.path, f.isFile()
print filePath, exist

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How to check if a file is exist in data folder by code?

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