Hey,

this is a task that I have to solve for a course at uni. It’s processing for beginners. We use Processing 3.

What do I do to connect each circle at y = 100 with those at y = 550? Apparently, a nested loop is a solution, but I have already tried and it didn’t work out for me.

This is what I have gotten so far. Below you can see a picture of what it is supposed to look like.

Appreciate your help.

Code:

```
size (1000,650);
background (255);
int spacing = 100;
int diameter = 50;
int x1 = -50;
int y1 = 100;
int y2 = 550;
int x2 = x1 += spacing;
ellipseMode (CENTER);
for (x1 = 50; x1 < width; x1 += spacing)
{
fill (120); ellipse (x1,y1,diameter,diameter);
ellipse (x1,y2,diameter,diameter);
line (x1,y1,x2,y2);
line (x2,y1,x1,y2);
}
```

1 Like

Please, when writing or editing a comment, use a little </> button above the text field to format your code into `monospace font, like this one`

.

Anyways, I think it makes sense to get rid of `int x1`

and `int x2`

definitions, and replace `for(x1 =..`

with `for(int x1 =..`

, and then put another for loop inside of that one `for(int x2=..`

. That second `for`

loop is a nested one.

Something like this:

```
size (1000, 650);
background (255);
int spacing = 100;
int diameter = 50;
int y1 = 100;
int y2 = 550;
ellipseMode (CENTER);
for (int x1 = 50; x1 < width; x1 += spacing)
{
fill (120);
ellipse (x1, y1, diameter, diameter);
ellipse (x1, y2, diameter, diameter);
for (int x2 = 50; x2 < width; x2 += spacing) {
line (x1, y1, x2, y2);
}
}
```

2 Likes

Thanks so much, Architector! However, seeing a possible solution, I realize I should have been able to figure that out, am a bit disappointed with myself haha. Also thank you for the advice on the formatting, this is my first post, so I didn’t know. Your help is much appreciated!!! Cheers

1 Like