I wrote this little function to convert miliseconds to Human readible time.
I would like to use “return” to make life simple.
So I tried:
void MsConversion(int MS)
{
int totalSec= (MS / 1000);
int seconds = (MS / 1000) % 60;
int minutes = (MS / (1000*60)) % 60;
int hours = ((MS/(1000*60*60)) % 24);
HumanTime= (hours+":" +nf(minutes, 2, 0)+ ":"+ nf(seconds, 2, 0));
return HumanTime;
//println (HumanTime);
}
but I get:
Void methods cannot return a value
Finally, I would want to use this function like this:
String ReadHere = MsConversion (8998798798);
and obtain a nice 8:44:43 for the string.
Is it possible?
Thanks
1 Like
Kevin
2
If you want to return a value from a function, you have to give your function a return type. In your case it would probably look like this:
String MsConversion(int MS) {
// ...
3 Likes
you just need to set the return type of the method
void returns nothing but you can replace it with just about any other type so replace void with String and your method will work
String MsConversion(int MS)
{
int totalSec= (MS / 1000);
int seconds = (MS / 1000) % 60;
int minutes = (MS / (1000*60)) % 60;
int hours = ((MS/(1000*60*60)) % 24);
HumanTime= (hours+":" +nf(minutes, 2, 0)+ ":"+ nf(seconds, 2, 0));
return HumanTime;
//println (HumanTime);
}
1 Like