String myString = "Lollipops and Candyfloss";
println(myString.substring(0,1), myString);
if (myString.substring(0,1).equals("L")) {
println("this is a test");
}
reference vs value testing
you could also do
if (myString.substring(0,1).charAt(0) == 'L') {
println("this is a test");
}
but i don’t know why you would. instead it would be better to skip the substring altogether if you are just testing a single character and use charAt instead or basically this instead of the first code in this post
String myString = "Lollipops and Candyfloss";
if (myString.charAt(0) == 'L') {
println("this is a test");
}