Sequence of actions from array

Processing Coding Questions
5

Thanks to all of you guys!
@Chrisir Your sketch gave me the solution. You misunderstood what I wanted: not the colors to appear one by one as listed, but for them to appear one by one in accordance to the array of random values. I just had to do a minor modification on your sketch, and found the solution I was looking for. But I couldn’t have done it without your help.

int[] array = new int[5];
int actionCounter = 0; 
int timer; 
int j;

void setup() {
  size(600, 600);
  background(128);
  for (int i = 0; i < array.length; i++) {
    array[i] = int(random(4));
  }
  println(array);

  timer = millis();
}

void draw() {
  background(128);
  showAction() ; 

  if (millis()-timer >= 1100) { 
    actionCounter++;
    timer = millis();
  }
}

void showAction() {
  if (actionCounter == 0) {
    j = 0;
    setColor();
    rect(200, 200, 100, 100);
  } else if (actionCounter == 1) { 
    j = 1;
    setColor();
    rect(200, 200, 100, 100);
  } else if (actionCounter == 2) {
    j = 2;
    setColor();
    rect(200, 200, 100, 100);
  } else if (actionCounter == 3) {
    j = 3;
    setColor();
    rect(200, 200, 100, 100);
  } else if (actionCounter == 4) {
    j = 4;
    setColor();
    rect(200, 200, 100, 100);
  }
}

void setColor() {

  if (array[j] == 0) {
    fill(0);
    rect(200, 200, 100, 100);
  }
  if (array[j] == 1) { 
    fill(255, 0, 0);
    rect(200, 200, 100, 100);
  }   
  if (array[j] == 2) {
    fill(0, 255, 0);
    rect(200, 200, 100, 100);
  }
  if (array[j] == 3) {
    fill(0, 0, 255);
    rect(200, 200, 100, 100);
  }
  if (array[j] == 4) {
    fill(255);
    rect(200, 200, 100, 100);
  }
}
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