# Print the value of a function
**URL:** https://discourse.processing.org/t/print-the-value-of-a-function/1902
**Category:** Beginners
**Created:** [July 19, 2018, 1:06pm UTC](https://discourse.processing.org/t/print-the-value-of-a-function/1902 "2018-07-19T13:06:03Z")
**Posts on this page:** 4
**Page:** 1
### Author:  [@Javier](https://discourse.processing.org/u/Javier)
#### Post date: [July 19, 2018, 1:06pm UTC](https://discourse.processing.org/t/print-the-value-of-a-function/1902/1 "2018-07-19T13:06:03Z")
Hi all¡¡ I have defined a very simple function that transfer fahrenheit to celsius and I want to introduce as a variable the Fharenheit and return Celsius. I would like to print the value of the Celsius but i cant undestand why i get 0 value…does someone knows where is the error? Thanks in advanced¡¡
float tempConverter(float F) {
float C=(F-32)\*(5/9);
return C;
}
void draw() {
float t=tempConverter(500);
println(t);
}
Thank you¡
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### Author:  [@jb4x](https://discourse.processing.org/u/jb4x)
#### Post date: [July 19, 2018, 1:09pm UTC](https://discourse.processing.org/t/print-the-value-of-a-function/1902/2 "2018-07-19T13:09:31Z")
Hi,
Try with 32.0, 5.0 and 9.0
I think you need to be sure that all your values are float numbers. Without .0 they are consider as int and thus you have troubles with your divisions.
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### Author:  [@Javier](https://discourse.processing.org/u/Javier)
#### Post date: [July 19, 2018, 4:26pm UTC](https://discourse.processing.org/t/print-the-value-of-a-function/1902/3 "2018-07-19T16:26:21Z")
Thanks a lot @jb4x i was getting mad cause I didn’t find the error. Thanks
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### Author:  [@jb4x](https://discourse.processing.org/u/jb4x)
#### Post date: [July 19, 2018, 4:59pm UTC](https://discourse.processing.org/t/print-the-value-of-a-function/1902/4 "2018-07-19T16:59:25Z")
With pleasure 🙂
When you are not use to it, it can be very, very annoying !