Hello guys, I am a little confused about the following. I need to get the number of floating digits of a float number. So I have for example the number: 12.345678 And I know that the number of int digits are 2 with the following code: float a = 12.345678; void setup() { int u=0; while(a/po…

int numb_d(float n){ int nb=0; while(((float)pow(10,nb))*n!=(int) (((float)pow(10,nb))*n)) nb++; return nb; } This method should suffice. It basicly always moves the comma one digit to the left and chops the digits after the comma of. And checks if choppign the digits of made a difference. I hope…

How to count the number of digits of a floating number?

Processing Coding Questions

juanjoc May 21, 2022, 3:20pm 7

Thanks @Chrisir for your reply. I was looking for a method that doesnt use any string coversion, but Its ok.

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How to count the number of digits of a floating number?

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