Hello guys, I am a little confused about the following. I need to get the number of floating digits of a float number. So I have for example the number: 12.345678 And I know that the number of int digits are 2 with the following code: float a = 12.345678; void setup() { int u=0; while(a/po…

int numb_d(float n){ int nb=0; while(((float)pow(10,nb))*n!=(int) (((float)pow(10,nb))*n)) nb++; return nb; } This method should suffice. It basicly always moves the comma one digit to the left and chops the digits after the comma of. And checks if choppign the digits of made a difference. I hope…

How to count the number of digits of a floating number?

Processing Coding Questions

glv May 18, 2025, 2:31pm 17

A fun addition to this topic:

:)

2 Likes

Topic		Replies	Views
How to get full float number expression? Beginners	1	376	October 24, 2020
Losing decimals Beginners	2	521	July 3, 2019
How to print with 2 decimals? Beginners	4	1171	September 12, 2019
Processing 4 Java Bug bad printing of a number Beginners	15	84	May 18, 2025
Show given number of significant numbers of float in text() Coding Questions	2	260	April 10, 2020

How to count the number of digits of a floating number?

Related topics