# How to check for similar number in array and bring out a error sign
**URL:** https://discourse.processing.org/t/how-to-check-for-similar-number-in-array-and-bring-out-a-error-sign/24454
**Category:** Beginners
**Tags:** homework
**Created:** [October 8, 2020, 10:24pm UTC](https://discourse.processing.org/t/how-to-check-for-similar-number-in-array-and-bring-out-a-error-sign/24454 "2020-10-08T22:24:08Z")
**Posts on this page:** 7
**Page:** 1
### Author:  [@newtothis](https://discourse.processing.org/u/newtothis)
#### Post date: [October 8, 2020, 10:24pm UTC](https://discourse.processing.org/t/how-to-check-for-similar-number-in-array-and-bring-out-a-error-sign/24454/1 "2020-10-08T22:24:08Z")
> please format code with \ button \* [homework policy](https://discourse.processing.org/faq/#homework) \* [asking questions](https://discourse.processing.org/t/2147)
```auto
for(int iIndex=0;iIndex<6; iIndex++) {
fill(67, 214, 250);
text(iArray[iIndex], (125 + 100 * iIndex), 200);
int iNext= iIndex+1;
while (iNext < 6 ) {
fill(255, 0, 0);
if (iArray[iIndex] == iArray[iNext]) { // getting a error here
text("ERROR, match between number " + (iIndex + 1) + " and " + (iNext + 1), 100.0,(400 + iCount * 30));
++iCount;
}
++iNext;
}
}
```
I’m using random function to store number in the array and the output has to be shown on the window , but when there is 2 similar numbers i have to show a error message.
That where I’m stuck right now because i’m getting “array index out bound expectation 6” error. So what condition i am suppose to put in while function ?
---
### Author:  [@Chrisir](https://discourse.processing.org/u/Chrisir)
#### Post date: [October 8, 2020, 10:41pm UTC](https://discourse.processing.org/t/how-to-check-for-similar-number-in-array-and-bring-out-a-error-sign/24454/2 "2020-10-08T22:41:52Z")
> [@newtothis](#):
>
> i’m getting “array index out bound expectation 6” error
In which line does it occur?
---
### Author:  [@Chrisir](https://discourse.processing.org/u/Chrisir)
#### Post date: [October 8, 2020, 10:46pm UTC](https://discourse.processing.org/t/how-to-check-for-similar-number-in-array-and-bring-out-a-error-sign/24454/4 "2020-10-08T22:46:17Z")
> [@newtothis](#):
>
> ` for(int iIndex=0;iIndex<6;`
Try \< 5
How did you declare the array?
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### Author:  [@Chrisir](https://discourse.processing.org/u/Chrisir)
#### Post date: [October 8, 2020, 10:46pm UTC](https://discourse.processing.org/t/how-to-check-for-similar-number-in-array-and-bring-out-a-error-sign/24454/5 "2020-10-08T22:46:55Z")
> [@newtothis](#):
>
> `while (iNext < 6 ) {`
Or try \< 5 here
Chrisir
---
### Author:  [@newtothis](https://discourse.processing.org/u/newtothis)
#### Post date: [October 8, 2020, 10:48pm UTC](https://discourse.processing.org/t/how-to-check-for-similar-number-in-array-and-bring-out-a-error-sign/24454/6 "2020-10-08T22:48:46Z")
this how i declare int[] iArray = new int[6];
i already tried 5 before but it’s still the same problem
---
### Author:  [@Chrisir](https://discourse.processing.org/u/Chrisir)
#### Post date: [October 8, 2020, 10:51pm UTC](https://discourse.processing.org/t/how-to-check-for-similar-number-in-array-and-bring-out-a-error-sign/24454/7 "2020-10-08T22:51:59Z")
6 means from 0 to 5
> [@newtothis](#):
>
> `for(int iIndex=0;iIndex<6; `
\<4
---
### Author:  [@newtothis](https://discourse.processing.org/u/newtothis)
#### Post date: [October 8, 2020, 10:59pm UTC](https://discourse.processing.org/t/how-to-check-for-similar-number-in-array-and-bring-out-a-error-sign/24454/8 "2020-10-08T22:59:10Z")
i have decreased the number each time going from 6 to 2 im getting a error message, however when i go to \<1, there is no "array index out bound expectation 6” but the error text message im suppose to show is not coming on the window