Thanks, @solub. Python is great!
Another Python solution:
def maxNonZeroSequence(nums):
return max(len(s) for s in ("".join(["0" if n == 0 else "1" for n in nums])).split("0"))
EDIT (2x on April 8, 2021):
So as to provide @batmm with something useful that can easily be converted to Java, here’s a p5.js solution:
function maximumConsecutiveNonZero(nums) {
let ct = 0;
let mx = 0;
for (let i = 0; i < nums.length; i += 1) {
if (nums[i] == 0) {
ct = 0;
} else {
ct += 1;
if (ct > mx) {
mx = ct;
}
}
}
return mx;
}