10 PRINT CHR$(205.5+RND(1)); : GOTO 10 Can this be done in Processing? :grin: @jeremydouglass

That is some code golf right there. [image] paulstgeorge: Wow! Is that the leanest? Ever? You can still shave off the size and set n=10 to take advantage of the default size=100x100. for(int x=1,y=0,n=10;x<n*n;x++){int r=int(random(2))*n,t=x%n*n;line(t+r,y,t+n-r,y+n);if(t==0)y+=n;} That’s …

y=0 …. wondering won‘t 0 be the default anyway so skip =0

[image] jeremydouglass: for(int x=1,y=0,n=10;x<n*n;x++){int r=int(random(2))*n,t=x%n*n;line(t+r,y,t+n-r,y+n);if(t==0)y+=n;} That would work in Python, but Java is “belt and braces” and requires int initialization. Java is a pretty tough language for a good code golf score. :wink:

People! Brevity is the soul of wit, golf, and much code. But many of the solutions here have something extra, and that is elegance. I suppose elegance is a short apparently simple statement (equation, sonnet, code, etc.) that when unpacked is huge and complex. An example would be the most beautiful…

OK. Here goes: Is there an elegant way to generate the permutations of all the members of a set? @jeremydouglass

Almost 3 years later! Leaner (108 characters) than my last version (113 characters). size(530,530);for(int i=0,y=0,n=23;i<n*n;i++){int r=(int)random(2)*n,x=i%n*n;y=i/n*n;line(x+r,y,x+n-r,y+n);} size(530, 530); for(int i=0, y=0, n=23; i<n*n; i++) { int r=(int)random(2)*n, x=i%n*n; y=i/n*n; …

100 char: size(530,530);for(int j=-1,m=23,r=0;j<530;r=random(2)>1?m:0)line(j%m*m+r,j/m*m,j%m*m+m-r,j++/m*m+m); which is size(530,530); for(int j=-1, m=23, r=0; j<530; r=random(2)>1?m:0) line(j%m*m+r, j/m*m, j%m*m+m-r, j++/m*m+m);

109 char (p5js) setup=_=>{for(createCanvas(M=530,M),j=0,m=23;j<M;)r=random([0,m]),x=j%m*m,line(x+r,y=int(j++/m)*m,x+m-r,y+m)} setup=_=>{ for(createCanvas(M=530,M),j=0,m=23;j<M;) r=random([0,m]), x=j%m*m, line(x+r,y=int(j++/m)*m,x+m-r,y+m) }

@micuat Nice! 99 char: size(530,530);for(int j=0,m=23,r=0;j<m*m;r=random(2)>1?m:0)line(j%m*m+r,j/m*m,j%m*m+m-r,j++/m*m+m); size(530, 530); for(int j=0, m=23, r=0; j<m*m; r=random(2)>1?m:0) line(j%m*m+r, j/m*m, j%m*m+m-r, j++/m*m+m); You can see the symmetry with this code I used for testing: …

10 print chr$(205.5+rnd(1)); : goto 10

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10 print chr$(205.5+rnd(1)); : goto 10

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